1/3+(5x)/6 >-(5x)/6-1/3
Let's solve in ℝ: 13 + 5x6 > -5x6 -13
ⓘ To add fractions, put them over the same denominator, then add the numerators: 13 + 5x6 = 2 + 5x6, -5x6 -13 = -5x + 2·(-1)6
2 + 5x6 > -5x + 2·(-1)6
ⓘ Multiplications are done before additions and subtractions. A single minus sign does not cancel out, the product of a negative number by a positive number is negative: 2·(-1) = -2■The minus sign is factored out, changing the sign of each term: -5x -2 = -(5x + 2)
2 + 5x6 > -5x + 26
Let's sum the fractions: 2 + 5x6 + 5x + 26 > 0
ⓘ Like terms are grouped by adding their coefficients: 2 + 5x6 + 5x + 26 = 2 + 5x3
2 + 5x3 > 0
⇥The expression 2 + 5x is zero at:
⇥ x = -25
⇥Its coefficient of x, 5, being positive, it is negative before and positive after -25
▶Solution found: x > -25
The numeric value of: x > -25 equals:
▷ x > -0.4