100x^2-160x+63=0
1) Let's solve in ℝ: 100x2 -160x + 63 = 0
Given the quadratic form ax2 + bx + c, you can calculate the discriminant: Δ = b2 -4ac. Here a = 100, b = -160 and c = 63
Δ = (-160)2 -4·100·63
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: (-160)2 = (-160)·(-160) = 25,600■Multiplications are done before additions and subtractions: 4·100 = 400
Δ = 25,600 -400·63
ⓘ Multiplications are done before additions and subtractions: 400·63 = 400·(60 + 3) = 400·60 + 400·3 = 24,000 + 1200 = 25,200
Δ = 25,600 -25,200
ⓘ Start from 25,600 and move back 25,200 on the number line: 25,600 -25,200 = 400
Δ = 400
Since Δ > 0, the equation has two roots:
The quadratic formula gives x1 = -b -Δ2a = -(-160) -4002·100
x1 = 160 -4002·100
ⓘ The square root of a number is the positive number whose square is that number: 400 = 20; 202 = 400
ⅰ 2·100 = 200
x1 = 160 -20200
ⓘ The numerator and the denominator are computed before the division: 160 -20 = 140
x1 = 140200
We divide the numerator and denominator of 140200 by the common factor: 20, which gives the new quotient: 710
x1 = 710
The quadratic formula gives x2 = -b + Δ2a = -(-160) + 4002·100
x2 = 160 + 4002·100
ⓘ The square root of a number is the positive number whose square is that number: 400 = 20; 202 = 400
ⅰ 2·100 = 200
x2 = 160 + 20200
ⓘ The numerator and the denominator are computed before the division: 160 + 20 = 180
x2 = 180200
The fraction: 180200 simplifies by the common factor: 20 into the new fraction: 910
x2 = 910
▶Solutions obtained: x = { 710, 910 }
2) The numeric value of: x = { 710, 910 } equals:
▷ x = { 0.7, 0.9 }