10x-2(3+5x)=-6
Let's solve in ℝ: 10x -2·(3 + 5x) = -6
ⓘ We add 6 to both sides
10x -2·(3 + 5x) + 6 = 0
ⓘ Expand by multiplying each term inside the parentheses: -2·(3 + 5x) = -(6 + 10x)
10x -(6 + 10x) + 6 = 0
ⓘ A minus sign before a parenthesis changes the sign of each of its terms: -(6 + 10x) = -6 -10x
10x -6 -10x + 6 = 0
ⓘ Start from -6 and move forward 6 on the number line, up to zero: -6 + 6 = 0■Like terms are grouped by adding their coefficients: 10x -10x = 0
0 + 0 = 0
ⓘ Adding 0 changes nothing: 0 + 0 = 0
0 = 0
▶Solution obtained: x ∈ ℝ