16(x+2)-8=16x+24
Let's solve in ℝ: 16·(x + 2) -8 = 16x + 24
16·(x + 2) -8 -16x -24 = 0
ⓘ Start from -8 and move back 24 more on the number line, away from zero: -8 -24 = -32
16·(x + 2) -32 -16x = 0
ⓘ Expand by multiplying each term inside the parentheses: 16·(x + 2) = 16x + 32
16x + 32 -32 -16x = 0
ⓘ Start from 32 and move back 32 on the number line, down to zero: 32 -32 = 0■Like terms are grouped by adding their coefficients: 16x -16x = 0
0 + 0 = 0
ⓘ Adding 0 changes nothing: 0 + 0 = 0
0 = 0
▶Solution found: x ∈ ℝ