2-5(x+5)=3(x-2)-1
Let's solve in ℝ: 2 -5·(x + 5) = 3·(x -2) -1
ⓘ Expand by multiplying each term inside the parentheses: -5·(x + 5) = -(5x + 25), 3·(x -2) = 3x -6
2 -(5x + 25) = 3x -6 -1
ⓘ A minus sign before a parenthesis changes the sign of each of its terms: -(5x + 25) = -5x -25■Start from -6 and move back 1 more on the number line, away from zero: -6 -1 = -7
2 -5x -25 = 3x -7
ⓘ Start from 2 and move back 25 on the number line, going below zero: 2 -25 = -23
-23 -5x = 3x -7
ⓘ We gather the terms in x on the right and the other terms on the left
-23 + 7 = 3x + 5x
ⓘ Start from -23 and move forward 7 on the number line, getting closer to zero: -23 + 7 = -16■Like terms are grouped by adding their coefficients: 3x + 5x = 8x
-16 = 8x
ⓘ Both sides are divided by 8
x = -168
ⓘ We simplify the fraction by dividing the numerator and the denominator by 8, their greatest common divisor: -168 = -2
▶Solution obtained: x = -2