2(2-3x)-3(3-2x)=4(x+1)+3(4-5x)
Let's solve in ℝ: 2·(2 -3x) -3·(3 -2x) = 4·(x + 1) + 3·(4 -5x)
ⓘ Expand by multiplying each term inside the parentheses: 2·(2 -3x) = 4 -6x, -3·(3 -2x) = -(9 -6x), 4·(x + 1) = 4x + 4, 3·(4 -5x) = 12 -15x
4 -6x -(9 -6x) = 4x + 4 + 12 -15x
ⓘ A minus sign before a parenthesis changes the sign of each of its terms: -(9 -6x) = -9 + 6x■Start from 4 and move forward 12 on the number line: 4 + 12 = 16■Like terms are grouped by adding their coefficients: 4x -15x = -11x
4 -6x -9 + 6x = -11x + 16
ⓘ Start from 4 and move back 9 on the number line, going below zero: 4 -9 = -5■Like terms are grouped by adding their coefficients: -6x + 6x = 0
-5 + 0 = -11x + 16
ⓘ Adding 0 changes nothing: -5 + 0 = -5
-5 = -11x + 16
ⓘ We add 5 to both sides■Start from 16 and move forward 5 on the number line: 16 + 5 = 21
0 = -11x + 21
ⓘ We add 21 to both sides
11x = 21
ⓘ Both sides are divided by 11
▶Solution found: x = 2111
The numeric value of: x = 2111 is:
▷ x = ≈ 1.9091