2(u+3)=3(1-u)+23
Let's solve in ℝ: 2·(u + 3) = 3·(1 -u) + 23
ⓘ Expand by multiplying each term inside the parentheses: 2·(u + 3) = 2u + 6, 3·(1 -u) = 3 + 3·(-u)
2u + 6 = 3 + 3·(-u) + 23
ⓘ The minus sign is placed in front of the product: 3·(-u) = -3u■Start from 3 and move forward 23 on the number line: 3 + 23 = 26
2u + 6 = 26 -3u
ⓘ We subtract 6 from both sides■Start from 26 and move back 6 on the number line: 26 -6 = 20
2u = 20 -3u
ⓘ We add 3u to both sides
2u + 3u = 20
ⓘ Like terms are grouped by adding their coefficients: 2u + 3u = 5u
5u = 20
ⓘ Both sides are divided by 5
u = 205
ⓘ We simplify the fraction by dividing the numerator and the denominator by 5, their greatest common divisor: 205 = 4
▶Solution obtained: u = 4