2|3x-4|+7=9
1) Let's solve in ℝ: 2·|3x -4| + 7 = 9
ⓘ We subtract 7 from both sides
2·|3x -4| = 9 -7
ⓘ Start from 9 and move back 7 on the number line: 9 -7 = 2
2·|3x -4| = 2
Since 2 ≠ 0, divide both sides by 2: |3x -4| = 1
Since 1 ≥ 0, |3x -4| = 1 is equivalent to 3x -4 = 1 or 3x -4 = -1
2) Let's solve in ℝ: 3x -4 = 1
ⓘ We add 4 to both sides
3x = 1 + 4
ⓘ Start from 1 and move forward 4 on the number line: 1 + 4 = 5
3x = 5
ⓘ Both sides are divided by 3
Solution found: x = 53
3) Let's solve in ℝ: 3x -4 = -1
ⓘ We add 4 to both sides
3x = -1 + 4
ⓘ Start from -1 and move forward 4 on the number line, going past zero: -1 + 4 = 3
3x = 3
ⓘ Both sides are divided by 3
x = 33
ⓘ We simplify the fraction by dividing the numerator and the denominator by 3, their greatest common divisor: 33 = 1
Solution obtained: x = 1
▶Solution:   x = { 1, 53 }
4) The numeric value of: x = { 1, 53 } equals:
▷ x = { 1, ≈ 1.6667 }