2|v-7|-4>= 42
1) Let's solve in ℝ: 2·|v -7| -4 ≥ 42
ⓘ We add 4 to both sides
2·|v -7| ≥ 42 + 4
ⓘ Start from 42 and move forward 4 on the number line: 42 + 4 = 46
2·|v -7| ≥ 46
Since 2 > 0, divide both sides by 2 without reversing the inequality: |v -7| ≥ 23
|A| ≥ B means that: A ≥ B or A ≤ -B
2) Let's solve in ℝ: v -7 ≥ 23
ⓘ We add 7 to both sides
v ≥ 23 + 7
ⓘ Start from 23 and move forward 7 on the number line: 23 + 7 = 30
Solution obtained: v ≥ 30
3) Let's solve in ℝ: v -7 ≤ -23
ⓘ We add 7 to both sides
v ≤ -23 + 7
ⓘ Start from -23 and move forward 7 on the number line, getting closer to zero: -23 + 7 = -16
Solution found: v ≤ -16
▶Solution:   v ∈ (-∞, -16] ∪ [30, +∞)