2 plus the integral of x
⇥Let's integrate: ∫xdx
⇥ⓘ An antiderivative of x^n is x^(n+1)/(n+1), for n ≠ -1: ∫xdx = x22
⇥ x22
⇥Indefinite integrals are defined up to an additive constant C, so this yields: x22 + C
Let's calculate: 2 + x22 + C
▶Result:   x22 + 2 + C, with C being any constant