2x(3+1) = 16
Let's solve in ℝ: 2x·(3 + 1) = 16
ⓘ Parentheses are computed first: 3 + 1 = 4
2x·4 = 16
ⅰ 2·4 = 8
8x = 16
ⓘ Both sides are divided by 8
x = 168
ⓘ We simplify the fraction by dividing the numerator and the denominator by 8, their greatest common divisor: 168 = 2
▶Solution obtained: x = 2