2x^2-12x+11=0
1) Let's solve in ℝ: 2x2 -12x + 11 = 0
Given the quadratic form ax2 + bx + c, you can calculate the discriminant: Δ = b2 -4ac. Here a = 2, b = -12 and c = 11
Δ = (-12)2 -4·2·11
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: (-12)2 = (-12)·(-12) = 144■Multiplications are done before additions and subtractions: 4·2 = 8
Δ = 144 -8·11
ⓘ Multiplications are done before additions and subtractions: 8·11 = 8·(10 + 1) = 8·10 + 8 = 80 + 8 = 88
Δ = 144 -88
ⓘ Start from 144 and move back 88 on the number line: 144 -88 = 56
Δ = 56
As Δ > 0, the equation has two roots:
The quadratic formula gives x1 = -b -Δ2a = -(-12) -562·2
x1 = 12 -562·2
ⓘ We look for the largest square dividing 56, 4 = 22, and take it out of the root: 56 = 4·14 = 4·14 = 2·14
ⅰ 2·2 = 4
x1 = 12 -2·144
ⓘ A fraction is simplified by dividing the numerator and the denominator by the same number: 12 -2·144 = 6 -142
x1 = 6 -142
The quadratic formula gives x2 = -b + Δ2a = -(-12) + 562·2
x2 = 12 + 562·2
ⓘ We look for the largest square dividing 56, 4 = 22, and take it out of the root: 56 = 4·14 = 4·14 = 2·14
ⅰ 2·2 = 4
x2 = 12 + 2·144
ⓘ A fraction is simplified by dividing the numerator and the denominator by the same number: 12 + 2·144 = 6 + 142
x2 = 6 + 142
▶Solutions obtained: x = { 6 -142, 6 + 142 }
2) The numeric value of: x = { 6 -142, 6 + 142 } equals:
x = { ≈ 6 -3.74172, ≈ 6 + 3.74172 }
x = { ≈ 2.25832, ≈ 9.74172 }
▷ x = { ≈ 1.1292, ≈ 4.8708 }