2x^2-4x=1
1) Let's solve in ℝ: 2x2 -4x = 1
2x2 -4x -1 = 0
Given the quadratic form ax2 + bx + c, you can calculate the discriminant: Δ = b2 -4ac. Here a = 2, b = -4 and c = -1
Δ = (-4)2 -4·2·(-1)
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: (-4)2 = (-4)·(-4) = 16■Multiplications are done before additions and subtractions: 4·2 = 8■Multiplying by -1 gives the opposite: -8·(-1) = 8
Δ = 16 + 8
ⓘ Start from 16 and move forward 8 on the number line: 16 + 8 = 24
Δ = 24
Since Δ > 0, the equation has two roots:
The quadratic formula gives x1 = -b -Δ2a = -(-4) -242·2
x1 = 4 -242·2
ⓘ We look for the largest square dividing 24, 4 = 22, and take it out of the root: 24 = 4·6 = 4·6 = 2·6
ⅰ 2·2 = 4
x1 = 4 -2·64
ⓘ A fraction is simplified by dividing the numerator and the denominator by the same number: 4 -2·64 = 2 -62
x1 = 2 -62
The quadratic formula gives x2 = -b + Δ2a = -(-4) + 242·2
x2 = 4 + 242·2
ⓘ We look for the largest square dividing 24, 4 = 22, and take it out of the root: 24 = 4·6 = 4·6 = 2·6
ⅰ 2·2 = 4
x2 = 4 + 2·64
ⓘ A fraction is simplified by dividing the numerator and the denominator by the same number: 4 + 2·64 = 2 + 62
x2 = 2 + 62
▶Solutions obtained: x = { 2 -62, 2 + 62 }
2) The numeric value of: x = { 2 -62, 2 + 62 } equals:
x = { ≈ 2 -2.44952, ≈ 2 + 2.44952 }
x = { ≈ -0.44952, ≈ 4.44952 }
▷ x = { ≈ -0.2247, ≈ 2.2247 }