2x^2+3x-2>0
1) Let's solve in ℝ: 2x2 + 3x -2 > 0
Given the quadratic form ax2 + bx + c, you can calculate the discriminant: Δ = b2 -4ac. Here a = 2, b = 3 and c = -2
Δ = 32 -4·2·(-2)
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 32 = 3·3 = 9■Multiplications are done before additions and subtractions: 4·2 = 8■Two minus signs cancel out, the product of two negative numbers is positive: -8·(-2) = 8·2
Δ = 9 + 8·2
ⓘ Multiplications are done before additions and subtractions: 8·2 = 16
Δ = 9 + 16
ⓘ Start from 9 and move forward 16 on the number line: 9 + 16 = 25
Δ = 25
As Δ > 0, the equation has two roots:
The quadratic formula gives x1 = -b -Δ2a = -3 -252·2
x1 = -3 -252·2
ⓘ The square root of a number is the positive number whose square is that number: 25 = 5; 52 = 25
ⅰ 2·2 = 4
x1 = -3 -54
ⓘ The numerator and the denominator are computed before the division: -3 -5 = -8
x1 = -84
ⓘ We simplify the fraction by dividing the numerator and the denominator by 4, their greatest common divisor: -84 = -2
x1 = -2
The quadratic formula gives x2 = -b + Δ2a = -3 + 252·2
x2 = -3 + 252·2
ⓘ The square root of a number is the positive number whose square is that number: 25 = 5; 52 = 25
ⅰ 2·2 = 4
x2 = -3 + 54
ⓘ The numerator and the denominator are computed before the division: -3 + 5 = 2
x2 = 24
ⓘ We simplify the fraction by dividing the numerator and the denominator by 2, their greatest common divisor: 24 = 1·22·2 = 12
x2 = 12
The quadratic has the sign of a = 2 outside its roots, so it is indeed positive outside its roots; the roots, where it is zero, are excluded.
▶Solution obtained: x ∈ (-∞, -2) ∪ (12, +∞)
2) The numeric value of: x ∈ (-∞, -2) ∪ (12, +∞) is:
▷ x ∈ (-∞, -2) ∪ (0.5, +∞)