3(1+x)-5=3x-2
Let's solve in ℝ: 3·(1 + x) -5 = 3x -2
3·(1 + x) -5 -3x + 2 = 0
ⓘ Start from -5 and move forward 2 on the number line, getting closer to zero: -5 + 2 = -3
3·(1 + x) -3 -3x = 0
ⓘ Expand by multiplying each term inside the parentheses: 3·(1 + x) = 3 + 3x
3 + 3x -3 -3x = 0
ⓘ Start from 3 and move back 3 on the number line, down to zero: 3 -3 = 0■Like terms are grouped by adding their coefficients: 3x -3x = 0
0 + 0 = 0
ⓘ Adding 0 changes nothing: 0 + 0 = 0
0 = 0
▶Solution found: x ∈ ℝ