3(3u+2)+5=2(2u-2)
Let's solve in ℝ: 3·(3u + 2) + 5 = 2·(2u -2)
ⓘ Expand by multiplying each term inside the parentheses: 3·(3u + 2) = 9u + 6, 2·(2u -2) = 4u -4
9u + 6 + 5 = 4u -4
ⓘ Start from 6 and move forward 5 on the number line: 6 + 5 = 11
9u + 11 = 4u -4
ⓘ We subtract 11 from both sides■Start from -4 and move back 11 more on the number line, away from zero: -4 -11 = -15
9u = 4u -15
ⓘ We subtract 4u from both sides
9u -4u = -15
ⓘ Like terms are grouped by adding their coefficients: 9u -4u = 5u
5u = -15
ⓘ Both sides are divided by 5
u = -155
ⓘ We simplify the fraction by dividing the numerator and the denominator by 5, their greatest common divisor: -155 = -3
▶Solution found: u = -3