3(3x+1)=9-5(3x-3)
Let's solve in ℝ: 3·(3x + 1) = 9 -5·(3x -3)
ⓘ Expand by multiplying each term inside the parentheses: 3·(3x + 1) = 9x + 3, -5·(3x -3) = -(15x -15)
9x + 3 = 9 -(15x -15)
ⓘ A minus sign before a parenthesis changes the sign of each of its terms: -(15x -15) = -15x + 15
9x + 3 = 9 -15x + 15
ⓘ Start from 9 and move forward 15 on the number line: 9 + 15 = 24
9x + 3 = 24 -15x
ⓘ We subtract 3 from both sides■Start from 24 and move back 3 on the number line: 24 -3 = 21
9x = 21 -15x
ⓘ We add 15x to both sides
9x + 15x = 21
ⓘ Like terms are grouped by adding their coefficients: 9x + 15x = 24x
24x = 21
ⓘ Both sides are divided by 24
x = 2124
ⓘ We simplify the fraction by dividing the numerator and the denominator by 3, their greatest common divisor: 2124 = 7·38·3 = 78
▶Solution obtained: x = 78
The numeric value of: x = 78 is:
▷ x = 0.875