3(x-3)+1=5x-4+3(7-x)
Let's solve in ℝ: 3·(x -3) + 1 = 5x -4 + 3·(7 -x)
ⓘ Expand by multiplying each term inside the parentheses: 3·(x -3) = 3x -9, 3·(7 -x) = 21 + 3·(-x)
3x -9 + 1 = 5x -4 + 21 + 3·(-x)
ⓘ Start from -9 and move forward 1 on the number line, getting closer to zero: -9 + 1 = -8■Start from -4 and move forward 21 on the number line, going past zero: -4 + 21 = 17■The minus sign is placed in front of the product: 3·(-x) = -3x
3x -8 = 5x + 17 -3x
ⓘ Like terms are grouped by adding their coefficients: 5x -3x = 2x
3x -8 = 2x + 17
ⓘ We add 8 to both sides■Start from 17 and move forward 8 on the number line: 17 + 8 = 25
3x = 2x + 25
ⓘ We subtract 2x from both sides
3x -2x = 25
ⓘ Like terms are grouped by adding their coefficients: 3x -2x = x
▶Solution obtained: x = 25