3(x+2)^2-47=-44
Let's solve in ℝ: 3·(x + 2)2 -47 = -44
ⓘ We add 47 to both sides
3·(x + 2)2 = 3
ⓘ Both sides are divided by 3
(x + 2)2 = 1
ⓘ The two numbers whose square is 1 are -1 and 1
x + 2 = -1
ⓘ We subtract 2 from both sides
Solution found: x = -3
x + 2 = 1
ⓘ We subtract 2 from both sides
Solution obtained: x = -1
▶Solution:   x = { -3, -1 }