3y+1<3y+1
Let's solve in ℝ: 3y + 1 < 3y + 1
ⓘ We subtract 1 from both sides■Start from 1 and move back 1 on the number line, down to zero: 1 -1 = 0
3y < 3y + 0
ⓘ Adding 0 changes nothing: 3y + 0 = 3y
3y < 3y
3y -3y < 0
ⓘ Like terms are grouped by adding their coefficients: 3y -3y = 0
0 < 0
The statement 0 < 0 is false, whatever the value of y
▶Solution: y ∈ ∅