3z+1/2 =z+9/2
Let's solve in ℝ: 3z + 12 = z + 92
ⓘ We subtract 12 from both sides■To add fractions, put them over the same denominator, then add the numerators: 92 -12 = 9 -12
3z = z + 9 -12
ⓘ The numerator and the denominator are computed before the division: 9 -1 = 8
3z = z + 82
ⓘ We simplify the fraction by dividing the numerator and the denominator by 2, their greatest common divisor: 82 = 4
3z = z + 4
ⓘ We subtract z from both sides
3z -z = 4
ⓘ Like terms are grouped by adding their coefficients: 3z -z = 2z
2z = 4
ⓘ Both sides are divided by 2
z = 42
ⓘ We simplify the fraction by dividing the numerator and the denominator by 2, their greatest common divisor: 42 = 2
▶Solution obtained: z = 2