4(x-1)^2+1/3 = 7/9 — step-by-step solution | Explain MAths

4(x-1)^2+1/3 = 7/9

Let's solve in

ℝ

:

4 \cdot {(x - 1)}^{2} + \frac{1}{3} = \frac{7}{9}

ⓘ We subtract

\frac{1}{3}

from both sides

4 \cdot {(x - 1)}^{2} = \frac{4}{9}

ⓘ Both sides are divided by

4

{(x - 1)}^{2} = \frac{1}{9}

ⓘ The two numbers whose square is

\frac{1}{9}

are

- \frac{1}{3}

and

\frac{1}{3}

x - 1 = - \frac{1}{3}

ⓘ We add

1

to both sides

Solution obtained:

x = \frac{2}{3}

x - 1 = \frac{1}{3}

ⓘ We add

1

to both sides

Solution found:

x = \frac{4}{3}

▶Solution:

x = {\frac{2}{3}, \frac{4}{3}}

The numeric value of:

x = {\frac{2}{3}, \frac{4}{3}}

equals:

▷

x = {\approx 0.6667, \approx 1.3333}