4(y+1)+y=3(y-2)+2
Let's solve in ℝ: 4·(y + 1) + y = 3·(y -2) + 2
ⓘ Expand by multiplying each term inside the parentheses: 4·(y + 1) = 4y + 4, 3·(y -2) = 3y -6
4y + 4 + y = 3y -6 + 2
ⓘ Like terms are grouped by adding their coefficients: 4y + y = 5y■Start from -6 and move forward 2 on the number line, getting closer to zero: -6 + 2 = -4
5y + 4 = 3y -4
ⓘ We subtract 4 from both sides■Start from -4 and move back 4 more on the number line, away from zero: -4 -4 = -8
5y = 3y -8
ⓘ We subtract 3y from both sides
5y -3y = -8
ⓘ Like terms are grouped by adding their coefficients: 5y -3y = 2y
2y = -8
ⓘ Both sides are divided by 2
y = -82
ⓘ We simplify the fraction by dividing the numerator and the denominator by 2, their greatest common divisor: -82 = -4
▶Solution found: y = -4