4x^2+16x-9=0
1) Let's solve in ℝ: 4x2 + 16x -9 = 0
Given the quadratic form ax2 + bx + c, you can calculate the discriminant: Δ = b2 -4ac. Here a = 4, b = 16 and c = -9
Δ = 162 -4·4·(-9)
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 162 = 16·16 = 256■Multiplications are done before additions and subtractions: 4·4 = 16■Two minus signs cancel out, the product of two negative numbers is positive: -16·(-9) = 16·9
Δ = 256 + 16·9
ⓘ Multiplications are done before additions and subtractions: 16·9 = (10 + 6)·9 = 10·9 + 6·9 = 90 + 54 = 144
Δ = 256 + 144
ⓘ Start from 256 and move forward 144 on the number line: 256 + 144 = 400
Δ = 400
Since Δ > 0, the equation has two roots:
The quadratic formula gives x1 = -b -Δ2a = -16 -4002·4
x1 = -16 -4002·4
ⓘ The square root of a number is the positive number whose square is that number: 400 = 20; 202 = 400
ⅰ 2·4 = 8
x1 = -16 -208
ⓘ The numerator and the denominator are computed before the division: -16 -20 = -36
x1 = -368
ⓘ We simplify the fraction by dividing the numerator and the denominator by 4, their greatest common divisor: -368 = -9·42·4 = -92
x1 = -92
The quadratic formula gives x2 = -b + Δ2a = -16 + 4002·4
x2 = -16 + 4002·4
ⓘ The square root of a number is the positive number whose square is that number: 400 = 20; 202 = 400
ⅰ 2·4 = 8
x2 = -16 + 208
ⓘ The numerator and the denominator are computed before the division: -16 + 20 = 4
x2 = 48
ⓘ We simplify the fraction by dividing the numerator and the denominator by 4, their greatest common divisor: 48 = 1·42·4 = 12
x2 = 12
▶Solutions obtained: x = { -92, 12 }
2) The numeric value of: x = { -92, 12 } equals:
▷ x = { -4.5, 0.5 }