4x^2+7x-2<= 0
1) Let's solve in ℝ: 4x2 + 7x -2 ≤ 0
Given the quadratic form ax2 + bx + c, you can calculate the discriminant: Δ = b2 -4ac. Here a = 4, b = 7 and c = -2
Δ = 72 -4·4·(-2)
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 72 = 7·7 = 49■Multiplications are done before additions and subtractions: 4·4 = 16■Two minus signs cancel out, the product of two negative numbers is positive: -16·(-2) = 16·2
Δ = 49 + 16·2
ⓘ Multiplications are done before additions and subtractions: 16·2 = (10 + 6)·2 = 10·2 + 6·2 = 20 + 12 = 32
Δ = 49 + 32
ⓘ Start from 49 and move forward 32 on the number line: 49 + 32 = 81
Δ = 81
As Δ > 0, the equation has two roots:
The quadratic formula gives x1 = -b -Δ2a = -7 -812·4
x1 = -7 -812·4
ⓘ The square root of a number is the positive number whose square is that number: 81 = 9; 92 = 81
ⅰ 2·4 = 8
x1 = -7 -98
ⓘ The numerator and the denominator are computed before the division: -7 -9 = -16
x1 = -168
ⓘ We simplify the fraction by dividing the numerator and the denominator by 8, their greatest common divisor: -168 = -2
x1 = -2
The quadratic formula gives x2 = -b + Δ2a = -7 + 812·4
x2 = -7 + 812·4
ⓘ The square root of a number is the positive number whose square is that number: 81 = 9; 92 = 81
ⅰ 2·4 = 8
x2 = -7 + 98
ⓘ The numerator and the denominator are computed before the division: -7 + 9 = 2
x2 = 28
ⓘ We simplify the fraction by dividing the numerator and the denominator by 2, their greatest common divisor: 28 = 1·24·2 = 14
x2 = 14
The quadratic has the opposite sign to a = 4 between its roots, so it is indeed negative between its roots; the roots, where it is zero, are included.
▶Solution found: x ∈ [-2, 14]
2) The numeric value of: x ∈ [-2, 14] equals:
▷ x ∈ [-2, 0.25]