5x^2=x-2
Let's solve in ℝ: 5x2 = x -2
5x2 -x + 2 = 0
Given the quadratic form ax2 + bx + c, you can calculate the discriminant: Δ = b2 -4ac. Here a = 5, b = -1 and c = 2
Δ = (-1)2 -4·5·2
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: (-1)2 = (-1)·(-1) = 1■Multiplications are done before additions and subtractions: 4·5 = 20
Δ = 1 -20·2
ⓘ Multiplications are done before additions and subtractions: 20·2 = 40
Δ = 1 -40
ⓘ Start from 1 and move back 40 on the number line, going below zero: 1 -40 = -39
Δ = -39
As Δ < 0, the equation has no real root.
▶Solution: x ∈ ∅