5x^2-35x+60=0
Let's solve in ℝ: 5x2 -35x + 60 = 0
Since 5 ≠ 0, divide both sides by 5: x2 -7x + 12 = 0
Given the quadratic form ax2 + bx + c, let's compute the discriminant: Δ = b2 -4ac. Here a = 1, b = -7 and c = 12
Δ = (-7)2 -4·1·12
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: (-7)2 = (-7)·(-7) = 49
Δ = 49 -4·12
ⓘ Multiplications are done before additions and subtractions: 4·12 = 4·(10 + 2) = 4·10 + 4·2 = 40 + 8 = 48
Δ = 49 -48
ⓘ Start from 49 and move back 48 on the number line: 49 -48 = 1
Δ = 1
As Δ > 0, the equation has two roots:
The quadratic formula gives x1 = -b -Δ2a = -(-7) -12·1
x1 = 7 -12
ⓘ The numerator and the denominator are computed before the division: 7 -1 = 6
x1 = 62
ⓘ We simplify the fraction by dividing the numerator and the denominator by 2, their greatest common divisor: 62 = 3
x1 = 3
The quadratic formula gives x2 = -b + Δ2a = -(-7) + 12·1
x2 = 7 + 12
ⓘ The numerator and the denominator are computed before the division: 7 + 1 = 8
x2 = 82
ⓘ We simplify the fraction by dividing the numerator and the denominator by 2, their greatest common divisor: 82 = 4
x2 = 4
▶Solutions found: x = { 3, 4 }