5x^2+x+4=0
Let's solve in ℝ: 5x2 + x + 4 = 0
Given the quadratic form ax2 + bx + c, let's compute the discriminant: Δ = b2 -4ac. Here a = 5, b = 1 and c = 4
Δ = 1 -4·5·4
ⓘ Multiplications are done before additions and subtractions: 5·4 = 20
Δ = 1 -20·4
ⓘ Multiplications are done before additions and subtractions: 20·4 = 80
Δ = 1 -80
ⓘ Start from 1 and move back 80 on the number line, going below zero: 1 -80 = -79
Δ = -79
As Δ < 0, the equation has no real root.
▶Solution: x ∈ ∅