6(-y+4)-3(2y-3)=-y+5+5y
Let's solve in ℝ: 6·(-y + 4) -3·(2y -3) = -y + 5 + 5y
ⓘ Like terms are grouped by adding their coefficients: -y + 5y = 4y
6·(-y + 4) -3·(2y -3) = 4y + 5
ⓘ Expand by multiplying each term inside the parentheses: 6·(-y + 4) = 6·(-y) + 24, -3·(2y -3) = -(6y -9)
6·(-y) + 24 -(6y -9) = 4y + 5
ⓘ The minus sign is placed in front of the product: 6·(-y) = -6y■A minus sign before a parenthesis changes the sign of each of its terms: -(6y -9) = -6y + 9
-6y + 24 -6y + 9 = 4y + 5
ⓘ Start from 24 and move forward 9 on the number line: 24 + 9 = 33■Like terms are grouped by adding their coefficients: -6y -6y = -12y
-12y + 33 = 4y + 5
ⓘ We gather the terms in y on the right and the other terms on the left
33 -5 = 4y + 12y
ⓘ Start from 33 and move back 5 on the number line: 33 -5 = 28■Like terms are grouped by adding their coefficients: 4y + 12y = 16y
28 = 16y
ⓘ Both sides are divided by 16
y = 2816
ⓘ We simplify the fraction by dividing the numerator and the denominator by 4, their greatest common divisor: 2816 = 7·44·4 = 74
▶Solution found: y = 74
The numeric value of: y = 74 is:
▷ y = 1.75