6x-2(x+9)=6x-18
Let's solve in ℝ: 6x -2·(x + 9) = 6x -18
6x -2·(x + 9) -6x + 18 = 0
ⓘ Like terms are grouped by adding their coefficients: 6x -6x = 0
0 -2·(x + 9) + 18 = 0
ⓘ Adding 0 changes nothing: 0 -2·(x + 9) = -2·(x + 9)
-2·(x + 9) + 18 = 0
ⓘ Expand by multiplying each term inside the parentheses: -2·(x + 9) = -(2x + 18)
-(2x + 18) + 18 = 0
ⓘ A minus sign before a parenthesis changes the sign of each of its terms: -(2x + 18) = -2x -18
-2x -18 + 18 = 0
ⓘ Start from -18 and move forward 18 on the number line, up to zero: -18 + 18 = 0
-2x + 0 = 0
ⓘ Adding 0 changes nothing: -2x + 0 = -2x
-2x = 0
We simplify the expression by -2
⇥Let's solve in ℝ: x = 0
▶Solution found: x = 0