6x^2+40x+50=0
1) Let's solve in ℝ: 6x2 + 40x + 50 = 0
Since 2 ≠ 0, divide both sides by 2: 3x2 + 20x + 25 = 0
Given the quadratic form ax2 + bx + c, let's compute the discriminant: Δ = b2 -4ac. Here a = 3, b = 20 and c = 25
Δ = 202 -4·3·25
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 202 = 20·20 = 400■Multiplications are done before additions and subtractions: 4·3 = 12
Δ = 400 -12·25
ⓘ Multiplications are done before additions and subtractions: 12·25 = (10 + 2)·25 = 10·25 + 2·25 = 250 + 50 = 300
Δ = 400 -300
ⓘ Start from 400 and move back 300 on the number line: 400 -300 = 100
Δ = 100
Since Δ > 0, the equation has two roots:
The quadratic formula gives x1 = -b -Δ2a = -20 -1002·3
x1 = -20 -1002·3
ⓘ The square root of a number is the positive number whose square is that number: 100 = 10; 102 = 100
ⅰ 2·3 = 6
x1 = -20 -106
ⓘ The numerator and the denominator are computed before the division: -20 -10 = -30
x1 = -306
ⓘ We simplify the fraction by dividing the numerator and the denominator by 6, their greatest common divisor: -306 = -5
x1 = -5
The quadratic formula gives x2 = -b + Δ2a = -20 + 1002·3
x2 = -20 + 1002·3
ⓘ The square root of a number is the positive number whose square is that number: 100 = 10; 102 = 100
ⅰ 2·3 = 6
x2 = -20 + 106
ⓘ The numerator and the denominator are computed before the division: -20 + 10 = -10
x2 = -106
ⓘ We simplify the fraction by dividing the numerator and the denominator by 2, their greatest common divisor: -106 = -5·23·2 = -53
x2 = -53
▶Solutions found: x = { -5, -53 }
2) The numeric value of: x = { -5, -53 } is:
▷ x = { -5, ≈ -1.6667 }