7-(2x+9)=11x-5(1-x)
1) Let's solve in ℝ: 7 -(2x + 9) = 11x -5·(1 -x)
ⓘ A minus sign before a parenthesis changes the sign of each of its terms: -(2x + 9) = -2x -9
7 -2x -9 = 11x -5·(1 -x)
ⓘ Start from 7 and move back 9 on the number line, going below zero: 7 -9 = -2
-2 -2x = 11x -5·(1 -x)
ⓘ Expand by multiplying each term inside the parentheses: -5·(1 -x) = -(5 + 5·(-x))
-2 -2x = 11x -(5 + 5·(-x))
ⓘ A minus sign before a parenthesis changes the sign of each of its terms: -(5 + 5·(-x)) = -5 -5·(-x)
-2 -2x = 11x -5 -5·(-x)
ⓘ Two minus signs cancel out: -5·(-x) = 5x
-2 -2x = 11x -5 + 5x
ⓘ Like terms are grouped by adding their coefficients: 11x + 5x = 16x
-2 -2x = 16x -5
ⓘ We gather the terms in x on the right and the other terms on the left
-2 + 5 = 16x + 2x
ⓘ Start from -2 and move forward 5 on the number line, going past zero: -2 + 5 = 3■Like terms are grouped by adding their coefficients: 16x + 2x = 18x
3 = 18x
ⓘ Both sides are divided by 18
x = 318
ⓘ We simplify the fraction by dividing the numerator and the denominator by 3, their greatest common divisor: 318 = 1·36·3 = 16
▶Solution obtained: x = 16
2) The numeric value of: x = 16 equals:
▷ x = ≈ 0.1667