7(x+1)+2>= 6x+13
Let's solve in ℝ: 7·(x + 1) + 2 ≥ 6x + 13
ⓘ Expand by multiplying each term inside the parentheses: 7·(x + 1) = 7x + 7
7x + 7 + 2 ≥ 6x + 13
ⓘ Start from 7 and move forward 2 on the number line: 7 + 2 = 9
7x + 9 ≥ 6x + 13
ⓘ We subtract 9 from both sides■Start from 13 and move back 9 on the number line: 13 -9 = 4
7x ≥ 6x + 4
ⓘ We subtract 6x from both sides
7x -6x ≥ 4
ⓘ Like terms are grouped by adding their coefficients: 7x -6x = x
▶Solution obtained: x ≥ 4