89x^2+38x-45=0
1) Let's solve in ℝ: 89x2 + 38x -45 = 0
Given the quadratic form ax2 + bx + c, you can calculate the discriminant: Δ = b2 -4ac. Here a = 89, b = 38 and c = -45
Δ = 382 -4·89·(-45)
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 382 = 38·38 = 1444■Multiplications are done before additions and subtractions: 4·89 = 4·(80 + 9) = 4·80 + 4·9 = 320 + 36 = 356■Two minus signs cancel out, the product of two negative numbers is positive: -356·(-45) = 356·45
Δ = 1444 + 356·45
ⓘ Multiplications are done before additions and subtractions: 356·45 = 356·(40 + 5) = 356·40 + 356·5 = 14,240 + 1780 = 16,020
Δ = 1444 + 16,020
ⓘ Start from 1444 and move forward 16,020 on the number line: 1444 + 16,020 = 17,464
Δ = 17,464
Since Δ > 0, the equation has two roots:
The quadratic formula gives x1 = -b -Δ2a = -38 -17,4642·89
x1 = -38 -17,4642·89
ⓘ We look for the largest square dividing 17,464, 4 = 22, and take it out of the root: 17,464 = 4·4366 = 4·4366 = 2·4366■The minus sign is factored out, changing the sign of each term: -38 -2·4366 = -(38 + 2·4366)
ⅰ 2·89 = 2·(80 + 9) = 2·80 + 2·9 = 160 + 18 = 178
x1 = -38 + 2·4366178
ⓘ A fraction is simplified by dividing the numerator and the denominator by the same number: -38 + 2·4366178 = -19 + 436689
x1 = -19 + 436689
The quadratic formula gives x2 = -b + Δ2a = -38 + 17,4642·89
x2 = -38 + 17,4642·89
ⓘ We look for the largest square dividing 17,464, 4 = 22, and take it out of the root: 17,464 = 4·4366 = 4·4366 = 2·4366
ⅰ 2·89 = 2·(80 + 9) = 2·80 + 2·9 = 160 + 18 = 178
x2 = -38 + 2·4366178
ⓘ A fraction is simplified by dividing the numerator and the denominator by the same number: -38 + 2·4366178 = -19 + 436689
x2 = -19 + 436689
▶Solutions obtained: x = { -19 + 436689, 4366 -1989 }
2) The numeric value of: x = { -19 + 436689, 4366 -1989 } equals:
x = { ≈ -19 + 66.075789, ≈ 66.0757 -1989 }
x = { ≈ -85.075789, ≈ 47.075789 }
▷ x = { ≈ -0.9559, ≈ 0.5289 }