8s^2-44s+60=0
1) Let's solve in ℝ: 8s2 -44s + 60 = 0
Since 4 ≠ 0, divide both sides by 4: 2s2 -11s + 15 = 0
Given the quadratic form as2 + bs + c, let's compute the discriminant: Δ = b2 -4ac. Here a = 2, b = -11 and c = 15
Δ = (-11)2 -4·2·15
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: (-11)2 = (-11)·(-11) = 121■Multiplications are done before additions and subtractions: 4·2 = 8
Δ = 121 -8·15
ⓘ Multiplications are done before additions and subtractions: 8·15 = 8·(10 + 5) = 8·10 + 8·5 = 80 + 40 = 120
Δ = 121 -120
ⓘ Start from 121 and move back 120 on the number line: 121 -120 = 1
Δ = 1
As Δ > 0, the equation has two roots:
The quadratic formula gives s1 = -b -Δ2a = -(-11) -12·2
s1 = 11 -12·2
ⓘ The numerator and the denominator are computed before the division: 11 -1 = 10
ⅰ 2·2 = 4
s1 = 104
ⓘ We simplify the fraction by dividing the numerator and the denominator by 2, their greatest common divisor: 104 = 5·22·2 = 52
s1 = 52
The quadratic formula gives s2 = -b + Δ2a = -(-11) + 12·2
s2 = 11 + 12·2
ⓘ The numerator and the denominator are computed before the division: 11 + 1 = 12
ⅰ 2·2 = 4
s2 = 124
ⓘ We simplify the fraction by dividing the numerator and the denominator by 4, their greatest common divisor: 124 = 3
s2 = 3
▶Solutions found: s = { 52, 3 }
2) The numeric value of: s = { 52, 3 } equals:
▷ s = { 2.5, 3 }