Calculate the derivative of f(x) = x^3 - 4x^2 + x - 7

We have :

f (x) = x^{3}

- 4 x^{2}

+ x

- 7

Let's perform the differentiation:

{(x^{3} - 4 x^{2} + x - 7)}^{'}

{(x^{3})}^{'}

+ {(- 4 x^{2})}^{'}

+ 1

+ 0

ℹ

(x^3)'

+ (-4*x^2)'

+ 1

+ 0

(x^3)' + (-4*x^2)' + 1

‖

(x^3)'

3 x^{2}

‖

(-4*x^2)'

-4 (x^2)'

‖

(x^2)'

2 x

3 x^{2} - 4 \cdot 2 x + 1

▷Result: $3 x^{2} - 8 x + 1$