abs(-2x+1)<3
Let's solve in ℝ: abs(-2x + 1) < 3
abs(A) < B is equivalent to -B < A < B
-3 < -2x + 1 < 3
We add -1 to all three parts of the inequality
-4 < -2x < 2
We divide all three parts by -2, which is negative: both inequality signs reverse
-1 < x < 2
▶Solution obtained: x ∈ (-1, 2)