compute (x-1)(x+2)(x-3) then differentiate the result
⚠ (x-1)(x+2)(x-3) is read as (x-1)*(x+2)*(x-3): use (...)*(...) for multiplication, use (...)^(...) for a power
Let's evaluate:
ⓘ Multiply each term of the sum by the other factor, using the distributive law: =
ⓘ Multiplying powers with the same base adds the exponents: = ■Multiplication by 1 preserves the original value: = ■Multiplications are done before additions and subtractions: =
ⓘ Group like terms by adding their coefficients: =
ⓘ Multiply each term of the sum by the other factor, using the distributive law: =
ⓘ To multiply powers with the same base, add their exponents: = , = ■The minus sign is placed in front of the product: = ■Write the minus sign in front of the product: = ■Perform multiplications before additions and subtractions. Two minus signs cancel out, the product of two negative numbers is positive: =
ⓘ Group like terms by adding their coefficients: = ■Like terms are grouped by adding their coefficients: =
▶Result:
Let's perform the differentiation:
ⓘ Differentiate a sum by differentiating each term, then adding the derivatives: =
ⓘ The derivative of is : = , = ■A constant factor stays in front of the derivative: that of is : = , = ■Adding 0 changes nothing: =
ⓘ Perform multiplications before additions and subtractions: =
▶Derivative: