derivative of-2/(9(1+x)^{5/3)}
To ease differentiation, the expression -29·(1 + x)53 is turned into -29·(1 + x)-53
Let's differentiate: ddx(-29·(1 + x)-53)
Apply the differentiation rule: ddx(fn) = n·ddx(f)·f(n -1) with f = 1 + x
-29·(-53·ddx(1 + x)·(1 + x)(-53 -1))
ℹddx(1 + x) = 0 + 1‖-53 -1 = -5 -1·33
-29·(-53)·(0 + 1)·(1 + x)(-5 -1·33)
-29·(-53)·(1 + x)(-5 -1·33)
ℹ-1·3 = -3‖-29·(-53) = 1027
1027·(1 + x)(-5 -33)
ℹ1027·(1 + x)(-5 -33) = 10·(1 + x)(-5 -33)27‖-5 -3 = -8
10·(1 + x)-8327
10(1 + x)83·27
▶Derivative:   1027·(x + 1)83