derivative of 1/((1-2x^{3/2)})
⚠ 1/((1-2x^{3/2)}) is read as 1/((1-2x^(3/2))): use ^(...) to group an exponent, use * to multiply
To ease differentiation, the expression 11 -2x32 is turned into (1 -2x32)-1
Let's perform the differentiation: ddx((1 -2x32)-1)
We differentiate using: ddx(fn) = n·ddx(f)·fn -1 (where f = 1 -2x32)
ⓘ The derivative of x^n is n*x^(n-1): ddx((1 -2x32)-1) = -1·ddx(1 -2x32)·(1 -2x32)-2
-1·ddx(1 -2x32)·(1 -2x32)-2
ⓘ Multiplying by -1 gives the opposite: -1·ddx(1 -2x32)·(1 -2x32)-2 = -ddx(1 -2x32)·(1 -2x32)-2
-ddx(1 -2x32)·(1 -2x32)-2
ⓘ A negative exponent moves the power to the other side of the fraction bar, for a nonzero base: -ddx(1 -2x32)·(1 -2x32)-2 = -ddx(1 -2x32)(1 -2x32)2
-ddx(1 -2x32)(1 -2x32)2
ⓘ The derivative of a sum is the sum of the derivatives: ddx(1 -2x32) = 0 + ddx(-2x32)
-0 + ddx(-2x32)(1 -2x32)2
ⓘ Adding 0 changes nothing: 0 + ddx(-2x32) = ddx(-2x32)■A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(-2x32) = -2·ddx(x32)■The derivative of x^n is n*x^(n-1): ddx(x32) = 32·x32 -1
-(-2·32·x32 -1(1 -2x32)2)
ⓘ To add fractions, put them over the same denominator, then add the numerators: 32 -1 = 3 -1·22
ⅰ 2·32 = 1·3
-(-1·3·x3 -1·22(1 -2x32)2)
ⓘ Multiplications are done before additions and subtractions: 1·2 = 2■A single minus sign does not cancel out, the product of a negative number by a positive number is negative: -1·3x3 -22 = -3x3 -22
-(-3x3 -22(1 -2x32)2)
ⓘ Two minus signs cancel out: -(-3x3 -22(1 -2x32)2) = 3x3 -22(1 -2x32)2
3x3 -22(1 -2x32)2
ⓘ The numerator and the denominator are computed before the division: 3 -2 = 1
▶Derivative:   3x12(1 -2x32)2