derivative of 3\sqrt[3]{x^2}-2x
Let's differentiate: ddx(3·x23 -2x)
ⓘ The derivative of a sum is the sum of the derivatives: ddx(3·x23 -2x) = ddx(3·x23) + ddx(-2x)
ddx(3·x23) + ddx(-2x)
Apply the differentiation rule: ddx(fn) = n·ddx(f)·fn -1 with f = x2
ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(3·x23) = 3·ddx(x23), ddx(-2x) = -2■The derivative of x^n is n*x^(n-1): ddx(x23) = 13·ddx(x2)·(x2)-23
3·13·ddx(x2)·(x2)-23 -2
ⓘ Multiplications are done before additions and subtractions: 3·13 = 1■Multiplying by 1 changes nothing: 1·ddx(x2)·(x2)-23 = ddx(x2)·(x2)-23■A power of a power multiplies the exponents, (a^n)^m = a^(n*m): (x2)-23 = x2·(-23)
ddx(x2)·x2·(-23) -2
ⓘ The derivative of x^n is n*x^(n-1): ddx(x2) = 2x■The minus sign is placed in front of the product: 2·(-23) = -2·23
2x·x-2·23 -2
ⓘ Multiplying a fraction by a number multiplies its numerator: -2·23 = -2·23 = -43■Multiplying powers with the same base adds the exponents: xx-43 = x1 -43
2x1 -43 -2
ⓘ To add fractions, put them over the same denominator, then add the numerators: 1 -43 = 3 -43
2x3 -43 -2
ⓘ The numerator and the denominator are computed before the division: 3 -4 = -1
2x-13 -2
ⓘ The factor is moved to the numerator or the denominator by changing the sign of its exponent, for a nonzero base: 2x-13 = 2x3
▶Derivative:   2x3 -2