derivative of 3/(sqrt(1-x^2))
To ease differentiation, the expression 31 -x2 is turned into 3·(1 -x2)-12
Let's differentiate: ddx(3·(1 -x2)-12)
Apply the differentiation rule: ddx(fn) = n·ddx(f)·fn -1 with f = 1 -x2
ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(3·(1 -x2)-12) = 3·ddx((1 -x2)-12)■The derivative of x^n is n*x^(n-1): ddx((1 -x2)-12) = -12·ddx(1 -x2)·(1 -x2)-32
3·(-12·ddx(1 -x2)·(1 -x2)-32)
ⓘ The derivative of a sum is the sum of the derivatives: ddx(1 -x2) = 0 + ddx(-x2)
ⅰ 3·(-12) = -32
-32·(0 + ddx(-x2))·(1 -x2)-32
ⓘ Adding 0 changes nothing: 0 + ddx(-x2) = ddx(-x2)■The derivative of x^n is n*x^(n-1): ddx(-x2) = -2x
-32·(-2x)·(1 -x2)-32
ⅰ 32·(-2) = 3·(-1)
-3·(-1)·x·(1 -x2)-32
ⓘ Two minus signs cancel out, the product of two negative numbers is positive: -3·(-1) = 3
3x·(1 -x2)-32
ⓘ The factor is moved to the numerator or the denominator by changing the sign of its exponent, for a nonzero base: 3x·(1 -x2)-32 = 3x(1 -x2)32
▶Derivative:   3x(1 -x2)32