derivative of 5^t
Let's perform the differentiation: ddt(5t)
You can rewrite the expression: 5t as: et·ln(5)
ⅰ ddt(5t) = ddt(t·ln(5))·et·ln(5)
ddt(t·ln(5))·et·ln(5)
ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddt(t·ln(5)) = ln(5)■As exp and ln are inverse of each other, exp(n*ln(x)) = x^n: et·ln(5) = 5t
ln(5)·5t
▶Derivative:   5t·ln(5)