derivative of 5e^x+2/(\sqrt[3]{x})
To simplify differentiation, we rewrite 2x3 as 2x-13
Let's perform the differentiation: ddx(5ex + 2x-13)
ⓘ The derivative of a sum is the sum of the derivatives: ddx(5ex + 2x-13) = ddx(5ex) + ddx(2x-13)
ddx(5ex) + ddx(2x-13)
Apply the differentiation rule: ddx(fn) = n·ddx(f)·fn -1 with f = x
ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(5ex) = 5·ddx(ex), ddx(2x-13) = 2·ddx(x-13)■The derivative of exp(x) is exp(x): ddx(ex) = ex■The derivative of x^n is n*x^(n-1): ddx(x-13) = -13·x-43
5ex + 2·(-13·x-43)
ⓘ Multiplications are done before additions and subtractions: 2·(-13) = -23
5ex -23·x-43
ⓘ Multiplying a fraction by a term multiplies its numerator: 23·x-43 = 2x-433■The factor is moved to the numerator or the denominator by changing the sign of its exponent, for a nonzero base: -2x-433 = -23x43
▶Derivative:   5ex -23x43