derivative of 5x^2cos(7x)
1) Let's differentiate: ddx(5x2·cos(7x))
ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(5x2·cos(7x)) = 5·ddx(x2·cos(7x))
5·ddx(x2·cos(7x))
We differentiate u1 = x2 and v2 = cos(7x) using: ddx(u1·v2) = ddx(u1)·v2 + u1·ddx(v2)
2) Let's perform the differentiation u1: ddx(x2)
ⓘ The derivative of x^n is n*x^(n-1): ddx(x2) = 2x
2x
3) Let's differentiate v2: ddx(cos(7x))
We differentiate using: ddx(cos(f)) = -ddx(f)·sin(f) (where f = 7x)
ⓘ The derivative of cos(x) is -sin(x): ddx(cos(7x)) = -ddx(7x)·sin(7x)
-ddx(7x)·sin(7x)
ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(7x) = 7
-7·sin(7x)
4) Let's evaluate the resulting derivative (u1·v2)': 2x·cos(7x) + x2·(-7·sin(7x))
ⓘ The minus sign is placed in front of the product: x2·(-7)·sin(7x) = -7x2·sin(7x)
2x·cos(7x) -7x2·sin(7x)
5) Then you can resume the differentiation:
ⅰ ddx(x2·cos(7x)) = 2x·cos(7x) -7x2·sin(7x)
5·(2x·cos(7x) -7x2·sin(7x))
ⓘ Expand by multiplying each term inside the parentheses: 5·(2x·cos(7x) -7x2·sin(7x)) = 10x·cos(7x) -35x2·sin(7x)
10x·cos(7x) -35x2·sin(7x)
This expression can be factorized into: x·(10·cos(7x) -35x·sin(7x))
Let's factor in ℝ: (10·cos(7x) -35x·sin(7x))
We factor out 5, the greatest common divisor of the coefficients: 10·cos(7x) -35x·sin(7x) = 5·(2·cos(7x) -7x·sin(7x))
Factor identified: 2·cos(7x) -7x·sin(7x)
▶Derivative:   5x·(2·cos(7x) -7x·sin(7x))