derivative of cos(arctan(3x))
⚠ 3x is read as the product 3*x: for a power, write 3^x
Let's differentiate: ddx(cos(arctan(3x)))
Apply the differentiation rule: ddx(cos(f)) = -ddx(f)·sin(f) with f = arctan(3x)
-ddx(arctan(3x))·sin(arctan(3x))
Apply the differentiation rule: ddx(arctan(f)) = ddx(f)·1f2 + 1 with f = 3x
-ddx(3x)(3x)2 + 1·sin(arctan(3x))
ℹ-ddx(3x)(3x)2 + 1·sin(arctan(3x)) = -ddx(3x)·sin(arctan(3x))(3x)2 + 1‖ddx(3x) = 3
-3·sin(arctan(3x))(3x)2 + 1
-3·sin(arctan(3x))32·x2 + 1
▶Derivative:   -3·sin(arctan(3x))9x2 + 1