derivative of cos^9(x^2y^6)
The expression cos(x2y6)9 contains several variables: the variable x is chosen for derivation
Let's perform the differentiation: ddx(cos(x2y6)9)
We differentiate using: ddx(fn) = n·ddx(f)·fn -1 (where f = cos(x2y6))
ⓘ The derivative of x^n is n*x^(n-1): ddx(cos(x2y6)9) = 9·ddx(cos(x2y6))·cos(x2y6)8
9·ddx(cos(x2y6))·cos(x2y6)8
We differentiate using: ddx(cos(f)) = -ddx(f)·sin(f) (where f = x2y6)
ⓘ The derivative of cos(x) is -sin(x): ddx(cos(x2y6)) = -ddx(x2y6)·sin(x2y6)
9·(-ddx(x2y6)·sin(x2y6))·cos(x2y6)8
ⓘ The minus sign is placed in front of the product: 9·(-ddx(x2y6)) = -9·ddx(x2y6)
-9·ddx(x2y6)·sin(x2y6)·cos(x2y6)8
ⓘ For differentiation with respect to x, y6 is treated as constant. A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(x2y6) = y6·ddx(x2)■The derivative of x^n is n*x^(n-1): ddx(x2) = 2x
-9·y6·2x·sin(x2y6)·cos(x2y6)8
ⅰ 9·2 = 18
-18y6x·sin(x2y6)·cos(x2y6)8
▶Derivative:   -18xy6·cos(x2y6)8·sin(x2y6)