derivative of ln(ln(sec(2x)))
Let's differentiate: ddx(ln(ln(sec(2x))))
Apply the differentiation rule: ddx(ln(f)) = ddx(f)·1f with f = ln(sec(2x))
ⓘ The derivative of ln(x) is 1/x: ddx(ln(ln(sec(2x)))) = ddx(ln(sec(2x)))·1ln(sec(2x))
ddx(ln(sec(2x)))·1ln(sec(2x))
Apply the differentiation rule: ddx(ln(f)) = ddx(f)·1f with f = sec(2x)
ⓘ Multiplying a fraction by a term multiplies its numerator: ddx(ln(sec(2x)))·1ln(sec(2x)) = ddx(ln(sec(2x)))·1ln(sec(2x)) = ddx(ln(sec(2x)))ln(sec(2x))■The derivative of ln(x) is 1/x: ddx(ln(sec(2x))) = ddx(sec(2x))·1sec(2x)
ddx(sec(2x))·1sec(2x)ln(sec(2x))
Apply the differentiation rule: ddx(sec(f)) = ddx(f)·sec(f)·tan(f) with f = 2x
ⓘ Multiplying a fraction by a term multiplies its numerator: ddx(sec(2x))·1sec(2x) = ddx(sec(2x))·1sec(2x) = ddx(sec(2x))sec(2x)■The derivative of sec(x) is sec(x)*tan(x): ddx(sec(2x)) = ddx(2x)·sec(2x)·tan(2x)
ddx(2x)·sec(2x)·tan(2x)sec(2x)ln(sec(2x))
ⓘ The original denominator must remain nonzero. The fraction is simplified by dividing the numerator and the denominator by their common factor sec(2x): ddx(2x)·sec(2x)·tan(2x)sec(2x) = ddx(2x)·tan(2x)
ddx(2x)·tan(2x)ln(sec(2x))
ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(2x) = 2
▶Derivative:   2·tan(2x)ln(sec(2x))