derivative of ln((ln(x)^2))
Let's perform the differentiation: ddx(ln(ln(x)2))
We differentiate using: ddx(ln(f)) = ddx(f)·1f (where f = ln(x)2)
ⓘ The derivative of ln(x) is 1/x: ddx(ln(ln(x)2)) = ddx(ln(x)2)·1ln(x)2
ddx(ln(x)2)·1ln(x)2
Apply the differentiation rule: ddx(fn) = n·ddx(f)·fn -1 with f = ln(x)
ⓘ Multiplying a fraction by a term multiplies its numerator: ddx(ln(x)2)·1ln(x)2 = ddx(ln(x)2)·1ln(x)2 = ddx(ln(x)2)ln(x)2■The derivative of x^n is n*x^(n-1): ddx(ln(x)2) = 2·ddx(ln(x))·ln(x)
2·ddx(ln(x))·ln(x)ln(x)2
We divide the numerator and denominator of ln(x)ln(x)2 by the common factor: ln(x), which gives the new fraction: 1ln(x)
2·ddx(ln(x))ln(x)
ⓘ The derivative of ln(x) is 1/x: ddx(ln(x)) = 1x
2·1xln(x)
ⓘ Multiplying a fraction by a number multiplies its numerator: 2·1x = 2·1x = 2x
2xln(x)
ⓘ Dividing a fraction by ln(x) is multiplying its denominator by ln(x): 2xln(x) = 2x·ln(x)
▶Derivative:   2x·ln(x)