derivative of ln(y/x)
The expression ln(yx) contains several variables: the variable x is chosen for derivation
1) Let's differentiate: ddx(ln(yx))
We differentiate using: ddx(ln(f)) = ddx(f)·1f (where f = yx)
ⓘ The derivative of ln(x) is 1/x: ddx(ln(yx)) = ddx(yx)·1yx
ddx(yx)·1yx
For p1 = y and q2 = x, use the differentiation rule: ddx(p1q2) = ddx(p1)·q2 -p1·ddx(q2)q22
2) Let's differentiate p1: ddx(y)
ⓘ The derivative of a constant is zero: ddx(y) = 0
0
3) Let's perform the differentiation q2: ddx(x)
ⓘ The derivative of x is 1: ddx(x) = 1
1
4) Let's evaluate the resulting derivative (p1q2)': 0·x -y·1x2
ⓘ A product with a zero factor is zero: 0·x = 0
0 -yx2
ⓘ Adding 0 changes nothing: 0 -y = -y
-yx2
5) Then you can continue the differentiation:
ⅰ ddx(yx) = -yx2
-yx2yx
ⓘ Dividing is multiplying by the reciprocal: -yx2yx = -yx2·xy
-yx2·xy
We divide the numerator and denominator of xx2 by the common factor: x, which gives the new fraction: 1x
▶Derivative:   -1x